(u^2+3u-40)/(2u^2-14u+20)

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Solution for (u^2+3u-40)/(2u^2-14u+20) equation:


D( u )

2*u^2-(14*u)+20 = 0

2*u^2-(14*u)+20 = 0

2*u^2-(14*u)+20 = 0

2*u^2-14*u+20 = 0

2*u^2-14*u+20 = 0

DELTA = (-14)^2-(2*4*20)

DELTA = 36

DELTA > 0

u = (36^(1/2)+14)/(2*2) or u = (14-36^(1/2))/(2*2)

u = 5 or u = 2

u in (-oo:2) U (2:5) U (5:+oo)

(u^2+3*u-40)/(2*u^2-(14*u)+20) = 0

(u^2+3*u-40)/(2*u^2-14*u+20) = 0

u^2+3*u-40 = 0

u^2+3*u-40 = 0

DELTA = 3^2-(-40*1*4)

DELTA = 169

DELTA > 0

u = (169^(1/2)-3)/(1*2) or u = (-169^(1/2)-3)/(1*2)

u = 5 or u = -8

(u+8)*(u-5) = 0

2*u^2-14*u+20 = 0

2*(u^2-7*u+10) = 0

u^2-7*u+10 = 0

DELTA = (-7)^2-(1*4*10)

DELTA = 9

DELTA > 0

u = (9^(1/2)+7)/(1*2) or u = (7-9^(1/2))/(1*2)

u = 5 or u = 2

2*(u-2)*(u-5) = 0

((u+8)*(u-5))/(2*(u-2)*(u-5)) = 0

( u+8 )

u+8 = 0 // - 8

u = -8

( u-5 )

u-5 = 0 // + 5

u = 5

u in { 5}

u = -8

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